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1/(2a-5)+7/9=2/(a+5)
We move all terms to the left:
1/(2a-5)+7/9-(2/(a+5))=0
Domain of the equation: (2a-5)!=0
We move all terms containing a to the left, all other terms to the right
2a!=5
a!=5/2
a!=2+1/2
a∈R
Domain of the equation: (a+5))!=0We calculate fractions
a∈R
9a/((2a-5)*(a+5))*9)+(-(2*(2a-5)*9)/((2a-5)*(a+5))*9)+(7*(2a-5)*(a+5)))/((2a-5)*(a+5))*9)=0
We can not solve this equation
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