If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/(15.84-x)=1/(5x)+.2
We move all terms to the left:
1/(15.84-x)-(1/(5x)+.2)=0
Domain of the equation: (15.84-x)!=0
We move all terms containing x to the left, all other terms to the right
-x!=-15.84
x!=-15.84/-1
x!=15+0.84/1
x∈R
Domain of the equation: 5x+.2)!=0We add all the numbers together, and all the variables
x∈R
1/(-1x+15.84)-(1/5x+0.2)=0
We get rid of parentheses
1/(-1x+15.84)-1/5x-0.2=0
We calculate fractions
5x/(-5x^2+79.2x)+(-1*(-1x+15.84))/(-5x^2+79.2x)-0.2=0
We calculate terms in parentheses: +(-1*(-1x+15.84))/(-5x^2+79.2x), so:We multiply all the terms by the denominator
-1*(-1x+15.84))/(-5x^2+79.2x
determiningTheFunctionDomain -5x^2-1*(-1x+15.84))/(+79.2x
We add all the numbers together, and all the variables
-5x^2+79.2x-1*(-1x+15.84))/(
We multiply all the terms by the denominator
-5x^2*(+(79.2x)*(-1*(-1x+15.84))
We add all the numbers together, and all the variables
-5x^2*(+(+79.2x)*(-1*(-1x+15.84))
Back to the equation:
+(-5x^2*(+(+79.2x)*(-1*(-1x+15.84)))
((-5x^2*(+(+79.2x)*(-1*(-1x+15.84)))-0.2)*(-5x^2+79.2x)+5x=0
| (x-1+√5)(x+1-√5)=0 | | 5(t+2)-3(2t+1)=-2 | | −3w+36=3w | | 3+(10-3x/2)=5 | | −0.06*x*x+1,2*x+4=6 | | q/8=19 | | -3=-0.5x^2+x+4 | | 3x^2-242=0 | | (15.84-x)^-1=(5x)^-1 | | -21=3v-1-8 | | 15x-(7x+11)=2(4x-3)-5 | | 3x-7÷9+x=3x+7÷3+3 | | y^2-22y-135=0 | | 5(2-x)=3x-(x+4) | | 1/5k-3=-31/3 | | (m-20/5)-(2m-14/4)=1 | | 9r-(4r-8)=7r | | -43-8x=-139 | | (2(-5/2)+5)(-m(3/2)+9)=0 | | 4x-9=2(2x-3)-3 | | -16+8x=-56 | | 5z-9+6z=-5+11z+6 | | (3y+5)(y+1)=3y^2-43 | | 2(8)+2(w)=80 | | -3(x-1)+3=2(x+1) | | 4x^2–27x+31=-7x+10 | | -7=-0.3x^2+3x+4 | | x^2+x-6=x+10 | | 3m/4-1=5m/6 | | 4x²–27x+31=-7x+10 | | 9.75x=10.5x-441 | | 7+2m/3=1m/10+24 |