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1.5t^2+5.0-84=0
We add all the numbers together, and all the variables
1.5t^2-79=0
a = 1.5; b = 0; c = -79;
Δ = b2-4ac
Δ = 02-4·1.5·(-79)
Δ = 474
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{474}}{2*1.5}=\frac{0-\sqrt{474}}{3} =-\frac{\sqrt{}}{3} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{474}}{2*1.5}=\frac{0+\sqrt{474}}{3} =\frac{\sqrt{}}{3} $
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