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1.5h(2-4h)=6h
We move all terms to the left:
1.5h(2-4h)-(6h)=0
We add all the numbers together, and all the variables
1.5h(-4h+2)-6h=0
We add all the numbers together, and all the variables
-6h+1.5h(-4h+2)=0
We multiply parentheses
-4h^2-6h+2h=0
We add all the numbers together, and all the variables
-4h^2-4h=0
a = -4; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·(-4)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*-4}=\frac{0}{-8} =0 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*-4}=\frac{8}{-8} =-1 $
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