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1.4x+x+(x-5)(x+35)=360
We move all terms to the left:
1.4x+x+(x-5)(x+35)-(360)=0
We add all the numbers together, and all the variables
2.4x+(x-5)(x+35)-360=0
We multiply parentheses ..
(+x^2+35x-5x-175)+2.4x-360=0
We get rid of parentheses
x^2+35x-5x+2.4x-175-360=0
We add all the numbers together, and all the variables
x^2+32.4x-535=0
a = 1; b = 32.4; c = -535;
Δ = b2-4ac
Δ = 32.42-4·1·(-535)
Δ = 3189.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32.4)-\sqrt{3189.76}}{2*1}=\frac{-32.4-\sqrt{3189.76}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32.4)+\sqrt{3189.76}}{2*1}=\frac{-32.4+\sqrt{3189.76}}{2} $
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