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1.3a+1=1/2a
We move all terms to the left:
1.3a+1-(1/2a)=0
Domain of the equation: 2a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1.3a-(+1/2a)+1=0
We get rid of parentheses
1.3a-1/2a+1=0
We multiply all the terms by the denominator
(1.3a)*2a+1*2a-1=0
We add all the numbers together, and all the variables
(+1.3a)*2a+1*2a-1=0
We multiply parentheses
2a^2+1*2a-1=0
Wy multiply elements
2a^2+2a-1=0
a = 2; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·2·(-1)
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3}}{2*2}=\frac{-2-2\sqrt{3}}{4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3}}{2*2}=\frac{-2+2\sqrt{3}}{4} $
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