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1.2x^2=4.2x
We move all terms to the left:
1.2x^2-(4.2x)=0
We add all the numbers together, and all the variables
1.2x^2-(+4.2x)=0
We get rid of parentheses
1.2x^2-4.2x=0
a = 1.2; b = -4.2; c = 0;
Δ = b2-4ac
Δ = -4.22-4·1.2·0
Δ = 17.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.2)-\sqrt{17.64}}{2*1.2}=\frac{4.2-\sqrt{17.64}}{2.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.2)+\sqrt{17.64}}{2*1.2}=\frac{4.2+\sqrt{17.64}}{2.4} $
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