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1.2m-6=2/3m-10
We move all terms to the left:
1.2m-6-(2/3m-10)=0
Domain of the equation: 3m-10)!=0We get rid of parentheses
m∈R
1.2m-2/3m+10-6=0
We multiply all the terms by the denominator
(1.2m)*3m+10*3m-6*3m-2=0
We add all the numbers together, and all the variables
(+1.2m)*3m+10*3m-6*3m-2=0
We multiply parentheses
3m^2+10*3m-6*3m-2=0
Wy multiply elements
3m^2+30m-18m-2=0
We add all the numbers together, and all the variables
3m^2+12m-2=0
a = 3; b = 12; c = -2;
Δ = b2-4ac
Δ = 122-4·3·(-2)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{42}}{2*3}=\frac{-12-2\sqrt{42}}{6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{42}}{2*3}=\frac{-12+2\sqrt{42}}{6} $
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