1.2=v2

Solution for 1.2=v2 equation:

1.2=v2

We move all terms to the left:

1.2-(v2)=0

We add all the numbers together, and all the variables

-1v^2+1.2=0

a = -1; b = 0; c = +1.2;
Δ = b2-4ac
Δ = 02-4·(-1)·1.2
Δ = 4.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.8}}{2*-1}=\frac{0-\sqrt{4.8}}{-2}
=-\frac{\sqrt{}}{-2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.8}}{2*-1}=\frac{0+\sqrt{4.8}}{-2}
=\frac{\sqrt{}}{-2}
$