1.024=h2

Solution for 1.024=h2 equation:

1.024=h2

We move all terms to the left:

1.024-(h2)=0

We add all the numbers together, and all the variables

-1h^2+1.024=0

a = -1; b = 0; c = +1.024;
Δ = b2-4ac
Δ = 02-4·(-1)·1.024
Δ = 4.096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.096}}{2*-1}=\frac{0-\sqrt{4.096}}{-2}
=-\frac{\sqrt{}}{-2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.096}}{2*-1}=\frac{0+\sqrt{4.096}}{-2}
=\frac{\sqrt{}}{-2}
$