1-k+4(k-1)=4(2+1)

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Solution for 1-k+4(k-1)=4(2+1) equation: 



1-k+4(k-1)=4(2+1)

We move all terms to the left:

1-k+4(k-1)-(4(2+1))=0

We add all the numbers together, and all the variables

-k+4(k-1)+1-(43)=0

We add all the numbers together, and all the variables

-1k+4(k-1)-42=0

We multiply parentheses

-1k+4k-4-42=0

We add all the numbers together, and all the variables

3k-46=0

We move all terms containing k to the left, all other terms to the right

3k=46

k=46/3

k=15+1/3

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