1-8x=-16x2

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Solution for 1-8x=-16x2 equation: 



1-8x=-16x^2

We move all terms to the left:

1-8x-(-16x^2)=0

We get rid of parentheses

16x^2-8x+1=0

a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{32}=1/4$

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