1-6x=4-(3-2x)

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Solution for 1-6x=4-(3-2x) equation: 



1-6x=4-(3-2x)

We move all terms to the left:

1-6x-(4-(3-2x))=0

We add all the numbers together, and all the variables

-6x-(4-(-2x+3))+1=0



We calculate terms in parentheses: -(4-(-2x+3)), so:

4-(-2x+3)

determiningTheFunctionDomain
-(-2x+3)+4

We get rid of parentheses

2x-3+4

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

-6x-2x-1+1=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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