1-5(3y+2)+3(4+y)=-12

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Solution for 1-5(3y+2)+3(4+y)=-12 equation:


Simplifying
1 + -5(3y + 2) + 3(4 + y) = -12

Reorder the terms:
1 + -5(2 + 3y) + 3(4 + y) = -12
1 + (2 * -5 + 3y * -5) + 3(4 + y) = -12
1 + (-10 + -15y) + 3(4 + y) = -12
1 + -10 + -15y + (4 * 3 + y * 3) = -12
1 + -10 + -15y + (12 + 3y) = -12

Reorder the terms:
1 + -10 + 12 + -15y + 3y = -12

Combine like terms: 1 + -10 = -9
-9 + 12 + -15y + 3y = -12

Combine like terms: -9 + 12 = 3
3 + -15y + 3y = -12

Combine like terms: -15y + 3y = -12y
3 + -12y = -12

Solving
3 + -12y = -12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -12y = -12 + -3

Combine like terms: 3 + -3 = 0
0 + -12y = -12 + -3
-12y = -12 + -3

Combine like terms: -12 + -3 = -15
-12y = -15

Divide each side by '-12'.
y = 1.25

Simplifying
y = 1.25

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