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1-3/2x=x-4
We move all terms to the left:
1-3/2x-(x-4)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-3/2x-x+4+1=0
We multiply all the terms by the denominator
-x*2x+4*2x+1*2x-3=0
Wy multiply elements
-2x^2+8x+2x-3=0
We add all the numbers together, and all the variables
-2x^2+10x-3=0
a = -2; b = 10; c = -3;
Δ = b2-4ac
Δ = 102-4·(-2)·(-3)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{19}}{2*-2}=\frac{-10-2\sqrt{19}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{19}}{2*-2}=\frac{-10+2\sqrt{19}}{-4} $
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