1-3(c-4)+8c=1-42+5(c+7)

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Solution for 1-3(c-4)+8c=1-42+5(c+7) equation:


Simplifying
1 + -3(c + -4) + 8c = 1 + -42 + 5(c + 7)

Reorder the terms:
1 + -3(-4 + c) + 8c = 1 + -42 + 5(c + 7)
1 + (-4 * -3 + c * -3) + 8c = 1 + -42 + 5(c + 7)
1 + (12 + -3c) + 8c = 1 + -42 + 5(c + 7)

Combine like terms: 1 + 12 = 13
13 + -3c + 8c = 1 + -42 + 5(c + 7)

Combine like terms: -3c + 8c = 5c
13 + 5c = 1 + -42 + 5(c + 7)

Reorder the terms:
13 + 5c = 1 + -42 + 5(7 + c)
13 + 5c = 1 + -42 + (7 * 5 + c * 5)
13 + 5c = 1 + -42 + (35 + 5c)

Combine like terms: 1 + -42 = -41
13 + 5c = -41 + 35 + 5c

Combine like terms: -41 + 35 = -6
13 + 5c = -6 + 5c

Add '-5c' to each side of the equation.
13 + 5c + -5c = -6 + 5c + -5c

Combine like terms: 5c + -5c = 0
13 + 0 = -6 + 5c + -5c
13 = -6 + 5c + -5c

Combine like terms: 5c + -5c = 0
13 = -6 + 0
13 = -6

Solving
13 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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