1-3(c+4)+8c=1-42+5(c+7)

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Solution for 1-3(c+4)+8c=1-42+5(c+7) equation:


Simplifying
1 + -3(c + 4) + 8c = 1 + -42 + 5(c + 7)

Reorder the terms:
1 + -3(4 + c) + 8c = 1 + -42 + 5(c + 7)
1 + (4 * -3 + c * -3) + 8c = 1 + -42 + 5(c + 7)
1 + (-12 + -3c) + 8c = 1 + -42 + 5(c + 7)

Combine like terms: 1 + -12 = -11
-11 + -3c + 8c = 1 + -42 + 5(c + 7)

Combine like terms: -3c + 8c = 5c
-11 + 5c = 1 + -42 + 5(c + 7)

Reorder the terms:
-11 + 5c = 1 + -42 + 5(7 + c)
-11 + 5c = 1 + -42 + (7 * 5 + c * 5)
-11 + 5c = 1 + -42 + (35 + 5c)

Combine like terms: 1 + -42 = -41
-11 + 5c = -41 + 35 + 5c

Combine like terms: -41 + 35 = -6
-11 + 5c = -6 + 5c

Add '-5c' to each side of the equation.
-11 + 5c + -5c = -6 + 5c + -5c

Combine like terms: 5c + -5c = 0
-11 + 0 = -6 + 5c + -5c
-11 = -6 + 5c + -5c

Combine like terms: 5c + -5c = 0
-11 = -6 + 0
-11 = -6

Solving
-11 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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