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1-2a-35a^2=0
a = -35; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·(-35)·1
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-12}{2*-35}=\frac{-10}{-70} =1/7 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+12}{2*-35}=\frac{14}{-70} =-1/5 $
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