1-2/x=10/3x-1/3

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Solution for 1-2/x=10/3x-1/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(2/x) = (10/3)*x-(1/3) // - (10/3)*x-(1/3)

1/3-((10/3)*x)-(2/x)+1 = 0

(-10/3)*x-2*x^-1+1/3+1 = 0

4/3*x^0-10/3*x^1-2*x^-1 = 0

(4/3*x^1-10/3*x^2-2*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^1-10/3*x^2-2*x^0) = 0

x^1

(-10/3)*x^2+(4/3)*x-2 = 0

(-10/3)*x^2+(4/3)*x-2 = 0

DELTA = (4/3)^2-(-2*4*(-10/3))

DELTA = -224/9

DELTA < 0

x in { } 

x belongs to the empty set

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