1-2+3(x-4)+5=6(x-7)-8

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Solution for 1-2+3(x-4)+5=6(x-7)-8 equation: 



1-2+3(x-4)+5=6(x-7)-8

We move all terms to the left:

1-2+3(x-4)+5-(6(x-7)-8)=0

We add all the numbers together, and all the variables

3(x-4)-(6(x-7)-8)+4=0

We multiply parentheses

3x-(6(x-7)-8)-12+4=0



We calculate terms in parentheses: -(6(x-7)-8), so:

6(x-7)-8

We multiply parentheses

6x-42-8

We add all the numbers together, and all the variables

6x-50

Back to the equation:

-(6x-50)



We add all the numbers together, and all the variables

3x-(6x-50)-8=0

We get rid of parentheses

3x-6x+50-8=0

We add all the numbers together, and all the variables

-3x+42=0

We move all terms containing x to the left, all other terms to the right

-3x=-42

x=-42/-3

x=+14

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