1-2(4q+12)=2+3(6-q)

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Solution for 1-2(4q+12)=2+3(6-q) equation: 



1-2(4q+12)=2+3(6-q)

We move all terms to the left:

1-2(4q+12)-(2+3(6-q))=0

We add all the numbers together, and all the variables

-2(4q+12)-(2+3(-1q+6))+1=0

We multiply parentheses

-8q-(2+3(-1q+6))-24+1=0



We calculate terms in parentheses: -(2+3(-1q+6)), so:

2+3(-1q+6)

determiningTheFunctionDomain
3(-1q+6)+2

We multiply parentheses

-3q+18+2

We add all the numbers together, and all the variables

-3q+20

Back to the equation:

-(-3q+20)



We add all the numbers together, and all the variables

-8q-(-3q+20)-23=0

We get rid of parentheses

-8q+3q-20-23=0

We add all the numbers together, and all the variables

-5q-43=0

We move all terms containing q to the left, all other terms to the right

-5q=43

q=43/-5

q=-8+3/5

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