1-2(3x-5)=3(-2x+1)+8

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Solution for 1-2(3x-5)=3(-2x+1)+8 equation: 


Simplifying
1 + -2(3x + -5) = 3(-2x + 1) + 8

Reorder the terms:
1 + -2(-5 + 3x) = 3(-2x + 1) + 8
1 + (-5 * -2 + 3x * -2) = 3(-2x + 1) + 8
1 + (10 + -6x) = 3(-2x + 1) + 8

Combine like terms: 1 + 10 = 11
11 + -6x = 3(-2x + 1) + 8

Reorder the terms:
11 + -6x = 3(1 + -2x) + 8
11 + -6x = (1 * 3 + -2x * 3) + 8
11 + -6x = (3 + -6x) + 8

Reorder the terms:
11 + -6x = 3 + 8 + -6x

Combine like terms: 3 + 8 = 11
11 + -6x = 11 + -6x

Add '-11' to each side of the equation.
11 + -11 + -6x = 11 + -11 + -6x

Combine like terms: 11 + -11 = 0
0 + -6x = 11 + -11 + -6x
-6x = 11 + -11 + -6x

Combine like terms: 11 + -11 = 0
-6x = 0 + -6x
-6x = -6x

Add '6x' to each side of the equation.
-6x + 6x = -6x + 6x

Combine like terms: -6x + 6x = 0
0 = -6x + 6x

Combine like terms: -6x + 6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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