1-13y=4(8y-6)+19y

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Solution for 1-13y=4(8y-6)+19y equation: 



1-13y=4(8y-6)+19y

We move all terms to the left:

1-13y-(4(8y-6)+19y)=0



We calculate terms in parentheses: -(4(8y-6)+19y), so:

4(8y-6)+19y

We add all the numbers together, and all the variables

19y+4(8y-6)

We multiply parentheses

19y+32y-24

We add all the numbers together, and all the variables

51y-24

Back to the equation:

-(51y-24)



We get rid of parentheses

-13y-51y+24+1=0

We add all the numbers together, and all the variables

-64y+25=0

We move all terms containing y to the left, all other terms to the right

-64y=-25

y=-25/-64

y=25/64

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