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1-1/2x=5/3x
We move all terms to the left:
1-1/2x-(5/3x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/2x-(+5/3x)+1=0
We get rid of parentheses
-1/2x-5/3x+1=0
We calculate fractions
(-3x)/6x^2+(-10x)/6x^2+1=0
We multiply all the terms by the denominator
(-3x)+(-10x)+1*6x^2=0
Wy multiply elements
6x^2+(-3x)+(-10x)=0
We get rid of parentheses
6x^2-3x-10x=0
We add all the numbers together, and all the variables
6x^2-13x=0
a = 6; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·6·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*6}=\frac{0}{12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*6}=\frac{26}{12} =2+1/6 $
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