1-1/(n+1)+1/(n+1)*(n+2)=n+1/n+2

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Solution for 1-1/(n+1)+1/(n+1)*(n+2)=n+1/n+2 equation: 



1-1/(n+1)+1/(n+1)(n+2)=n+1/n+2

We move all terms to the left:

1-1/(n+1)+1/(n+1)(n+2)-(n+1/n+2)=0



Domain of the equation: (n+1)!=0

We move all terms containing n to the left, all other terms to the right

n!=-1

n∈R





Domain of the equation: (n+1)(n+2)!=0

We move all terms containing n to the left, all other terms to the right

n+1)(n!=-2

n∈R





Domain of the equation: n+2)!=0

n∈R



We get rid of parentheses

-1/(n+1)+1/(n+1)(n+2)-n-1/n-2+1=0

We multiply parentheses ..

1/(+n^2+2n+n+2)-1/(n+1)-n-1/n-2+1=0

We calculate fractions

We do not support enpression: n^3

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