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1-(x+2)=4(x+3)
We move all terms to the left:
1-(x+2)-(4(x+3))=0
We get rid of parentheses
-x-(4(x+3))-2+1=0
We calculate terms in parentheses: -(4(x+3)), so:We add all the numbers together, and all the variables
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
-1x-(4x+12)-1=0
We get rid of parentheses
-1x-4x-12-1=0
We add all the numbers together, and all the variables
-5x-13=0
We move all terms containing x to the left, all other terms to the right
-5x=13
x=13/-5
x=-2+3/5
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