1-(t-6)-8=-(1+t)

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Solution for 1-(t-6)-8=-(1+t) equation: 



1-(t-6)-8=-(1+t)

We move all terms to the left:

1-(t-6)-8-(-(1+t))=0

We add all the numbers together, and all the variables

-(t-6)-(-(t+1))+1-8=0

We add all the numbers together, and all the variables

-(t-6)-(-(t+1))-7=0

We get rid of parentheses

-t-(-(t+1))+6-7=0



We calculate terms in parentheses: -(-(t+1)), so:

-(t+1)

We get rid of parentheses

-t-1

We add all the numbers together, and all the variables

-1t-1

Back to the equation:

-(-1t-1)



We add all the numbers together, and all the variables

-1t-(-1t-1)-1=0

We get rid of parentheses

-1t+1t+1-1=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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