1-(p+2)-(p-3)-(p-1)=0

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Solution for 1-(p+2)-(p-3)-(p-1)=0 equation: 



1-(p+2)-(p-3)-(p-1)=0

We get rid of parentheses

-p-p-p-2+3+1+1=0

We add all the numbers together, and all the variables

-3p+3=0

We move all terms containing p to the left, all other terms to the right

-3p=-3

p=-3/-3

p=1

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