1-(n+4)-(12-3n)=4n-5

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Solution for 1-(n+4)-(12-3n)=4n-5 equation:


Simplifying
1 + -1(n + 4) + -1(12 + -3n) = 4n + -5

Reorder the terms:
1 + -1(4 + n) + -1(12 + -3n) = 4n + -5
1 + (4 * -1 + n * -1) + -1(12 + -3n) = 4n + -5
1 + (-4 + -1n) + -1(12 + -3n) = 4n + -5
1 + -4 + -1n + (12 * -1 + -3n * -1) = 4n + -5
1 + -4 + -1n + (-12 + 3n) = 4n + -5

Reorder the terms:
1 + -4 + -12 + -1n + 3n = 4n + -5

Combine like terms: 1 + -4 = -3
-3 + -12 + -1n + 3n = 4n + -5

Combine like terms: -3 + -12 = -15
-15 + -1n + 3n = 4n + -5

Combine like terms: -1n + 3n = 2n
-15 + 2n = 4n + -5

Reorder the terms:
-15 + 2n = -5 + 4n

Solving
-15 + 2n = -5 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
-15 + 2n + -4n = -5 + 4n + -4n

Combine like terms: 2n + -4n = -2n
-15 + -2n = -5 + 4n + -4n

Combine like terms: 4n + -4n = 0
-15 + -2n = -5 + 0
-15 + -2n = -5

Add '15' to each side of the equation.
-15 + 15 + -2n = -5 + 15

Combine like terms: -15 + 15 = 0
0 + -2n = -5 + 15
-2n = -5 + 15

Combine like terms: -5 + 15 = 10
-2n = 10

Divide each side by '-2'.
n = -5

Simplifying
n = -5

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