1-(7x-8)*3=(6x-3)*2-(24x-12)*2

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Solution for 1-(7x-8)*3=(6x-3)*2-(24x-12)*2 equation: 



1-(7x-8)*3=(6x-3)*2-(24x-12)*2

We move all terms to the left:

1-(7x-8)*3-((6x-3)*2-(24x-12)*2)=0

We multiply parentheses

-21x-((6x-3)*2-(24x-12)*2)+24+1=0



We calculate terms in parentheses: -((6x-3)*2-(24x-12)*2), so:

(6x-3)*2-(24x-12)*2

We multiply parentheses

12x-48x-6+24

We add all the numbers together, and all the variables

-36x+18

Back to the equation:

-(-36x+18)



We add all the numbers together, and all the variables

-21x-(-36x+18)+25=0

We get rid of parentheses

-21x+36x-18+25=0

We add all the numbers together, and all the variables

15x+7=0

We move all terms containing x to the left, all other terms to the right

15x=-7

x=-7/15

x=-7/15

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