1-(7+3p)=6(2p-6)

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Solution for 1-(7+3p)=6(2p-6) equation: 



1-(7+3p)=6(2p-6)

We move all terms to the left:

1-(7+3p)-(6(2p-6))=0

We add all the numbers together, and all the variables

-(3p+7)-(6(2p-6))+1=0

We get rid of parentheses

-3p-(6(2p-6))-7+1=0



We calculate terms in parentheses: -(6(2p-6)), so:

6(2p-6)

We multiply parentheses

12p-36

Back to the equation:

-(12p-36)



We add all the numbers together, and all the variables

-3p-(12p-36)-6=0

We get rid of parentheses

-3p-12p+36-6=0

We add all the numbers together, and all the variables

-15p+30=0

We move all terms containing p to the left, all other terms to the right

-15p=-30

p=-30/-15

p=+2

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