1-(3/4)(v+2)=-5

Solution for 1-(3/4)(v+2)=-5 equation:

1-(3/4)(v+2)=-5

We move all terms to the left:

1-(3/4)(v+2)-(-5)=0


Domain of the equation: 4)(v+2)!=0

v∈R


We add all the numbers together, and all the variables

-(+3/4)(v+2)+1-(-5)=0

We add all the numbers together, and all the variables

-(+3/4)(v+2)+6=0

We multiply parentheses ..

-(+3v^2+3/4*2)+6=0

We multiply all the terms by the denominator


-(+3v^2+3+6*4*2)=0

We get rid of parentheses

-3v^2-3-6*4*2=0

We add all the numbers together, and all the variables

-3v^2-51=0

a = -3; b = 0; c = -51;
Δ = b2-4ac
Δ = 02-4·(-3)·(-51)
Δ = -612
Delta is less than zero, so there is no solution for the equation