1-(1/x)-(2/x2)=0

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Solution for 1-(1/x)-(2/x2)=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(1/x)-(2/(x^2)) = 0

1-x^-1-2*x^-2 = 0

t_1 = x^-1

1-2*t_1^2-1*t_1^1 = 0

1-2*t_1^2-t_1 = 0

DELTA = (-1)^2-(-2*1*4)

DELTA = 9

DELTA > 0

t_1 = (9^(1/2)+1)/(-2*2) or t_1 = (1-9^(1/2))/(-2*2)

t_1 = -1 or t_1 = 1/2

t_1 = -1

x^-1+1 = 0

1*x^-1 = -1 // : 1

x^-1 = -1

-1 < 0

1/(x^1) = -1 // * x^1

1 = -1*x^1 // : -1

-1 = x^1

x = -1

t_1 = 1/2

x^-1-1/2 = 0

1*x^-1 = 1/2 // : 1

x^-1 = 1/2

-1 < 0

1/(x^1) = 1/2 // * x^1

1 = 1/2*x^1 // : 1/2

2 = x^1

x = 2

x in { -1, 2 }

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