1,9104x2-4,1724x+2,2031=0

Solution for 1,9104x2-4,1724x+2,2031=0 equation:

1.9104x^2-4.1724x+2.2031=0

a = 1.9104; b = -4.1724; c = +2.2031;
Δ = b2-4ac
Δ = -4.17242-4·1.9104·2.2031
Δ = 0.5737128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.1724)-\sqrt{0.5737128}}{2*1.9104}=\frac{4.1724-\sqrt{0.5737128}}{3.8208}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.1724)+\sqrt{0.5737128}}{2*1.9104}=\frac{4.1724+\sqrt{0.5737128}}{3.8208}
$