1+cos(x)+cos(2x)+cos(3x)=0

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Solution for 1+cos(x)+cos(2x)+cos(3x)=0 equation:


Simplifying
1 + cos(x) + cos(2x) + cos(3x) = 0

Multiply cos * x
1 + cosx + cos(2x) + cos(3x) = 0

Remove parenthesis around (2x)
1 + cosx + cos * 2x + cos(3x) = 0

Reorder the terms for easier multiplication:
1 + cosx + 2cos * x + cos(3x) = 0

Multiply cos * x
1 + cosx + 2cosx + cos(3x) = 0

Remove parenthesis around (3x)
1 + cosx + 2cosx + cos * 3x = 0

Reorder the terms for easier multiplication:
1 + cosx + 2cosx + 3cos * x = 0

Multiply cos * x
1 + cosx + 2cosx + 3cosx = 0

Combine like terms: cosx + 2cosx = 3cosx
1 + 3cosx + 3cosx = 0

Combine like terms: 3cosx + 3cosx = 6cosx
1 + 6cosx = 0

Solving
1 + 6cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 6cosx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 6cosx = 0 + -1
6cosx = 0 + -1

Combine like terms: 0 + -1 = -1
6cosx = -1

Divide each side by '6osx'.
c = -0.1666666667o-1s-1x-1

Simplifying
c = -0.1666666667o-1s-1x-1

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