1+8x+x+7=4(5+x)+8(8x-3)

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Solution for 1+8x+x+7=4(5+x)+8(8x-3) equation: 



1+8x+x+7=4(5+x)+8(8x-3)

We move all terms to the left:

1+8x+x+7-(4(5+x)+8(8x-3))=0

We add all the numbers together, and all the variables

8x+x-(4(x+5)+8(8x-3))+1+7=0

We add all the numbers together, and all the variables

9x-(4(x+5)+8(8x-3))+8=0



We calculate terms in parentheses: -(4(x+5)+8(8x-3)), so:

4(x+5)+8(8x-3)

We multiply parentheses

4x+64x+20-24

We add all the numbers together, and all the variables

68x-4

Back to the equation:

-(68x-4)



We get rid of parentheses

9x-68x+4+8=0

We add all the numbers together, and all the variables

-59x+12=0

We move all terms containing x to the left, all other terms to the right

-59x=-12

x=-12/-59

x=12/59

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