1+8(-z-3)=-(3z-1)-7

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Solution for 1+8(-z-3)=-(3z-1)-7 equation: 



1+8(-z-3)=-(3z-1)-7

We move all terms to the left:

1+8(-z-3)-(-(3z-1)-7)=0

We add all the numbers together, and all the variables

8(-1z-3)-(-(3z-1)-7)+1=0

We multiply parentheses

-8z-(-(3z-1)-7)-24+1=0



We calculate terms in parentheses: -(-(3z-1)-7), so:

-(3z-1)-7

We get rid of parentheses

-3z+1-7

We add all the numbers together, and all the variables

-3z-6

Back to the equation:

-(-3z-6)



We add all the numbers together, and all the variables

-8z-(-3z-6)-23=0

We get rid of parentheses

-8z+3z+6-23=0

We add all the numbers together, and all the variables

-5z-17=0

We move all terms containing z to the left, all other terms to the right

-5z=17

z=17/-5

z=-3+2/5

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