1+7(f+1)=2(f-1)

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Solution for 1+7(f+1)=2(f-1) equation: 



1+7(f+1)=2(f-1)

We move all terms to the left:

1+7(f+1)-(2(f-1))=0

We multiply parentheses

7f-(2(f-1))+7+1=0



We calculate terms in parentheses: -(2(f-1)), so:

2(f-1)

We multiply parentheses

2f-2

Back to the equation:

-(2f-2)



We add all the numbers together, and all the variables

7f-(2f-2)+8=0

We get rid of parentheses

7f-2f+2+8=0

We add all the numbers together, and all the variables

5f+10=0

We move all terms containing f to the left, all other terms to the right

5f=-10

f=-10/5

f=-2

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