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1+6x-5x=6(3x+1)-5
We move all terms to the left:
1+6x-5x-(6(3x+1)-5)=0
We add all the numbers together, and all the variables
x-(6(3x+1)-5)+1=0
We calculate terms in parentheses: -(6(3x+1)-5), so:We get rid of parentheses
6(3x+1)-5
We multiply parentheses
18x+6-5
We add all the numbers together, and all the variables
18x+1
Back to the equation:
-(18x+1)
x-18x-1+1=0
We add all the numbers together, and all the variables
-17x=0
x=0/-17
x=0
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