1+6(4v-2)=109

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Solution for 1+6(4v-2)=109 equation: 



1+6(4v-2)=109

We move all terms to the left:

1+6(4v-2)-(109)=0

We add all the numbers together, and all the variables

6(4v-2)-108=0

We multiply parentheses

24v-12-108=0

We add all the numbers together, and all the variables

24v-120=0

We move all terms containing v to the left, all other terms to the right

24v=120

v=120/24

v=5

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