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1+5x-364+2-x2=2+x-122
We move all terms to the left:
1+5x-364+2-x2-(2+x-122)=0
We add all the numbers together, and all the variables
5x-x2-(x-120)+1-364+2=0
We add all the numbers together, and all the variables
-1x^2+5x-(x-120)-361=0
We get rid of parentheses
-1x^2+5x-x+120-361=0
We add all the numbers together, and all the variables
-1x^2+4x-241=0
a = -1; b = 4; c = -241;
Δ = b2-4ac
Δ = 42-4·(-1)·(-241)
Δ = -948
Delta is less than zero, so there is no solution for the equation
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