1+5(b+3)=8(b+2)

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Solution for 1+5(b+3)=8(b+2) equation:


Simplifying
1 + 5(b + 3) = 8(b + 2)

Reorder the terms:
1 + 5(3 + b) = 8(b + 2)
1 + (3 * 5 + b * 5) = 8(b + 2)
1 + (15 + 5b) = 8(b + 2)

Combine like terms: 1 + 15 = 16
16 + 5b = 8(b + 2)

Reorder the terms:
16 + 5b = 8(2 + b)
16 + 5b = (2 * 8 + b * 8)
16 + 5b = (16 + 8b)

Add '-16' to each side of the equation.
16 + -16 + 5b = 16 + -16 + 8b

Combine like terms: 16 + -16 = 0
0 + 5b = 16 + -16 + 8b
5b = 16 + -16 + 8b

Combine like terms: 16 + -16 = 0
5b = 0 + 8b
5b = 8b

Solving
5b = 8b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8b' to each side of the equation.
5b + -8b = 8b + -8b

Combine like terms: 5b + -8b = -3b
-3b = 8b + -8b

Combine like terms: 8b + -8b = 0
-3b = 0

Divide each side by '-3'.
b = 0

Simplifying
b = 0

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