1+5(2u-2)=-3(4u-1)+8u

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Solution for 1+5(2u-2)=-3(4u-1)+8u equation: 



1+5(2u-2)=-3(4u-1)+8u

We move all terms to the left:

1+5(2u-2)-(-3(4u-1)+8u)=0

We multiply parentheses

10u-(-3(4u-1)+8u)-10+1=0



We calculate terms in parentheses: -(-3(4u-1)+8u), so:

-3(4u-1)+8u

We add all the numbers together, and all the variables

8u-3(4u-1)

We multiply parentheses

8u-12u+3

We add all the numbers together, and all the variables

-4u+3

Back to the equation:

-(-4u+3)



We add all the numbers together, and all the variables

10u-(-4u+3)-9=0

We get rid of parentheses

10u+4u-3-9=0

We add all the numbers together, and all the variables

14u-12=0

We move all terms containing u to the left, all other terms to the right

14u=12

u=12/14

u=6/7

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