1+4/3x=3/2x-5

Solution for 1+4/3x=3/2x-5 equation:

1+4/3x=3/2x-5

We move all terms to the left:

1+4/3x-(3/2x-5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x-5)!=0

x∈R


We get rid of parentheses

4/3x-3/2x+5+1=0

We calculate fractions


8x/6x^2+(-9x)/6x^2+5+1=0

We add all the numbers together, and all the variables

8x/6x^2+(-9x)/6x^2+6=0

We multiply all the terms by the denominator


8x+(-9x)+6*6x^2=0

Wy multiply elements

36x^2+8x+(-9x)=0

We get rid of parentheses

36x^2+8x-9x=0

We add all the numbers together, and all the variables

36x^2-1x=0

a = 36; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·36·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*36}=\frac{2}{72}
=1/36
$