1+4(x-3)+7=40

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Solution for 1+4(x-3)+7=40 equation: 



1+4(x-3)+7=40

We move all terms to the left:

1+4(x-3)+7-(40)=0

We add all the numbers together, and all the variables

4(x-3)-32=0

We multiply parentheses

4x-12-32=0

We add all the numbers together, and all the variables

4x-44=0

We move all terms containing x to the left, all other terms to the right

4x=44

x=44/4

x=11

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