1+4(2u+1)=63

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Solution for 1+4(2u+1)=63 equation: 



1+4(2u+1)=63

We move all terms to the left:

1+4(2u+1)-(63)=0

We add all the numbers together, and all the variables

4(2u+1)-62=0

We multiply parentheses

8u+4-62=0

We add all the numbers together, and all the variables

8u-58=0

We move all terms containing u to the left, all other terms to the right

8u=58

u=58/8

u=7+1/4

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