1+3y+18=y-3(1+3y)

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Solution for 1+3y+18=y-3(1+3y) equation: 



1+3y+18=y-3(1+3y)

We move all terms to the left:

1+3y+18-(y-3(1+3y))=0

We add all the numbers together, and all the variables

3y-(y-3(3y+1))+1+18=0

We add all the numbers together, and all the variables

3y-(y-3(3y+1))+19=0



We calculate terms in parentheses: -(y-3(3y+1)), so:

y-3(3y+1)

We multiply parentheses

y-9y-3

We add all the numbers together, and all the variables

-8y-3

Back to the equation:

-(-8y-3)



We get rid of parentheses

3y+8y+3+19=0

We add all the numbers together, and all the variables

11y+22=0

We move all terms containing y to the left, all other terms to the right

11y=-22

y=-22/11

y=-2

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