1+3x(+9x)=60

Solution for 1+3x(+9x)=60 equation:

1+3x(+9x)=60

We move all terms to the left:

1+3x(+9x)-(60)=0

We add all the numbers together, and all the variables

3x(+9x)-59=0

We multiply parentheses

27x^2-59=0

a = 27; b = 0; c = -59;
Δ = b2-4ac
Δ = 02-4·27·(-59)
Δ = 6372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6372}=\sqrt{36*177}=\sqrt{36}*\sqrt{177}=6\sqrt{177}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{177}}{2*27}=\frac{0-6\sqrt{177}}{54}
=-\frac{6\sqrt{177}}{54}
=-\frac{\sqrt{177}}{9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{177}}{2*27}=\frac{0+6\sqrt{177}}{54}
=\frac{6\sqrt{177}}{54}
=\frac{\sqrt{177}}{9}
$