1+3c=5(1-1c)+8c

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Solution for 1+3c=5(1-1c)+8c equation: 



1+3c=5(1-1c)+8c

We move all terms to the left:

1+3c-(5(1-1c)+8c)=0

We add all the numbers together, and all the variables

3c-(5(-1c+1)+8c)+1=0



We calculate terms in parentheses: -(5(-1c+1)+8c), so:

5(-1c+1)+8c

We add all the numbers together, and all the variables

8c+5(-1c+1)

We multiply parentheses

8c-5c+5

We add all the numbers together, and all the variables

3c+5

Back to the equation:

-(3c+5)



We get rid of parentheses

3c-3c-5+1=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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