1+3+5+99y=y*y

Solution for 1+3+5+99y=y*y equation:

1+3+5+99y=y*y

We move all terms to the left:

1+3+5+99y-(y*y)=0

We add all the numbers together, and all the variables

99y-(+y*y)+1+3+5=0

We add all the numbers together, and all the variables

99y-(+y*y)+9=0

We get rid of parentheses

99y-y*y+9=0

Wy multiply elements

-1y^2+99y+9=0

a = -1; b = 99; c = +9;
Δ = b2-4ac
Δ = 992-4·(-1)·9
Δ = 9837
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9837}=\sqrt{9*1093}=\sqrt{9}*\sqrt{1093}=3\sqrt{1093}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-3\sqrt{1093}}{2*-1}=\frac{-99-3\sqrt{1093}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+3\sqrt{1093}}{2*-1}=\frac{-99+3\sqrt{1093}}{-2}
$